-10n^2=-430

Solution for -10n^2=-430 equation:

-10n^2=-430

We move all terms to the left:

-10n^2-(-430)=0

We add all the numbers together, and all the variables

-10n^2+430=0

a = -10; b = 0; c = +430;
Δ = b2-4ac
Δ = 02-4·(-10)·430
Δ = 17200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{17200}=\sqrt{400*43}=\sqrt{400}*\sqrt{43}=20\sqrt{43}$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{43}}{2*-10}=\frac{0-20\sqrt{43}}{-20}
=-\frac{20\sqrt{43}}{-20}
=-\frac{\sqrt{43}}{-1}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{43}}{2*-10}=\frac{0+20\sqrt{43}}{-20}
=\frac{20\sqrt{43}}{-20}
=\frac{\sqrt{43}}{-1}
$